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Given an array of size N in which every number is between 1
and N, determine if there are any duplicates in it. You are
allowed to destroy the array if you like.
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Answer Posted / hitesh
#include<iostream>
using namespace std;
int main()
{
int a[5],j,temp,flag,i,s ;
cout<<"Enter the size of the array :";
cin>>s; // size
for( i=0;i<s;i++){
cout<<"Enter the "<<i+1<<" element :";
cin>>a[i];
}
for( int i=0;i<s;i++){
temp=a[i];
for(j=i+1;j<s;j++){
if(a[j]==temp)
{flag=1;
break;
}
}
}
if(flag==1){cout<<"Duplicacy is there !! The duplicate number is :"<<temp;
}
else
cout<<"No duplicate value";
return 0;
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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