Answer Posted / suvra sankha chattopadhyay

For 1 cum of brick work ,C.M 1:6
Brick size= 9" 4.5" 3"
= 0.2286 x 0.1143 x 0.0762 cum.
Volume of Brick= 1.991028276 x 1/1000 cum.
Number of bricks= cum of Brick work/Volume of 1 Brick
= 502.2530378 or 503 number of Brick.

For 1 cum of brick work 25 to 30% C.M required
i.e; 0.3 cum of C.M.
Dry cement concrete required; due to 60% void in sand;
=0.3 + 0.3 X 60%
=0.48 cum C.M.

As the C.M is in the ratio of 1:6;
Volume of Cement required =0.48/(1+6)
=0.06857 cum
Cement bags required = 0.06857/0.0347
=1.976 or 2 Bags of Cement.

Volume of sand required = (0.48 x 6)/(1+7)
= 0.411428 cum.
or 14.5304 cft.

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