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Answer Posted / vinod maurya
We will short 1U & 2U
And we will apply 3 phase voltage between 1U,1V,1W
Measure between
1U-1V
1V-1W
1W-1U
1V-2v
1V-2w
1W-2w
1W-2v
1W-2n
2n-1U
Verify The Condition
1W-2n+2n-1U= 1U-1W
1W-2w=1W-2v
1V-2v<1V-2w
vector group Dyn1 confirmed if the above conditions are
satisfied.
| Is This Answer Correct ? | 8 Yes | 1 No |
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