Write a C program that defines a 2-dimentional integer array
called A [50][50]. Then the elements of this array should
randomly be initialized either to 1 or 0. The program should
then print out all the elements in the diagonal (i.e.
a[0][0], a[1][1],a[2][2], a[3][3], ……..a[49][49]). Finally,
print out how many zeros and ones in the diagonal.
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Answer Posted / senthil
// correcting Cfuzz answer
#include <stdio.h>
#include <stdlib.h> // for rand function
#define ROWS 50
#define COLS 50
int main(void)
{
int A[ROWS][COLS];
int i=0, j=0;
int zero_cnt = 0;
int one_cnt = 0;
/* Initializing*/
for(i=0; i < ROWS; i++) {
for(j=0; j < COLS; j++) {
A[i][j] = rand() % 2;
}
}
// here one loop is sufficient
for(i=0; i < ROWS; i++) {
printf("A[%d][%d] = %2d\n", i, i, A[i][i]);
if(A[i][i] == 0)
{
zero_cnt++;
}
else //if(A[i][i] == 1)
{
one_cnt++;
}
}
printf("\nNumber of zeros in the diagonal = %d", zero_cnt);
printf("\nNumber of ones in the diagonal = %d", one_cnt);
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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