why 1.25 factor is to be multiplied to cylindrical strength
of concrete while getting the equvalent cubical strength of
concrete?
Answer Posted / umair majeed
Governing factor of application of such factor is h/d ratio of both the cube and cylinder specimens. As h/d ratio increases, strength decreases. h/d ratio of cylinder is twice to that of cube. Moreover, when load is applied on cube specimens, compression imposed by platens of testing machine enhance the confinement which in turn increases the compressive strength of cubes. It is reported that for 3000psi concrete, ratio of strength of cylinder to that of cube is around 0.76. Hence whenever cube strength is taken as multiple of cylinder strength then a factor of 1.25 is incorporated to get approximate results.
| Is This Answer Correct ? | 1 Yes | 0 No |
Post New Answer View All Answers
how calucate cement sand ratio for plstering
If specific gravity of cement is less than 3.15 what is the cause?
where can i get the previous question papers for rrb section enginerr (civil)
how water proof chemicals act in concrete to avoid leek?
psc girder detail
How to fix toll charge for a particular vehicle at toll booths in a highway?
1m square 20mm plastering how much of water need curing work
How many bricks are there in 100cft?
Explain soil analysis?
why we can use dust in concrete insted of fly ash
what is project?
How to calculate steel for beam slab and column
What is command line?
how much required strength of cement concrete bricks(size 230x115x75mm)
rcc floor to floor 4m. in column reinforcement where we provide lap in exact location.