why 1.25 factor is to be multiplied to cylindrical strength
of concrete while getting the equvalent cubical strength of
concrete?
Answer Posted / umair majeed
Governing factor of application of such factor is h/d ratio of both the cube and cylinder specimens. As h/d ratio increases, strength decreases. h/d ratio of cylinder is twice to that of cube. Moreover, when load is applied on cube specimens, compression imposed by platens of testing machine enhance the confinement which in turn increases the compressive strength of cubes. It is reported that for 3000psi concrete, ratio of strength of cylinder to that of cube is around 0.76. Hence whenever cube strength is taken as multiple of cylinder strength then a factor of 1.25 is incorporated to get approximate results.
| Is This Answer Correct ? | 1 Yes | 0 No |
Post New Answer View All Answers
There are two buildings one taller and one shorter whose time period will be grater and similarly the frequency ?
Rate analysis of 150mm, 100mm, & 230mm thk BBM work
which steel is better for residential building tmt steel or hysd steel
i need gate exam civil engineering question papers with answers
How to calculate dry of volume of concrete constant?How it comes 1.54 or 1.57
In tower foundation, on the time of 3 mtr pit RCC casting if water and mud is their surface of PCC then what will be do?
What are the important hardware systems used for cad?
what is the weight of 6000 psi concrete in lb/cft?
What are the skills required to become an architect?
what is the formula for Mass of cement grout (Dg)=???
how to absorb to site basic corrections? which are the important correction?
What are the uses of alloys in daily life and how are alloys made?
States some of the tool bars used in cad?
How many % we consider for lap for reinforcement for estimates
what is thumb rule for calculating the size of ISMB required for a particular length of span