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Simple calculation of improving power factor?

Answer Posted / khalid mohammed yousf

S=V.I (AV)
S = (P^2 + Q^2)^(1/2)
cos &#981; =S/P
Q=(S^2-P^2)^(1/2)
Q=(E^2)/X
C=(1/2*PI*F*Xc)
C IS shunt capacitor using to improved power factor

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