Answer Posted / pradeep raj

int main()
{
char a[20],*p,*q;//p=>front pointer q=>back pointer
int flag=0;
cin >>a;
q=&a[0];
while(*q!='\0')
q++;
q--; // to the last character before null

for(p=&a[0];p!=q ;p++,q--)
{

if(*p==*q)
flag++;
if((q-p)==1)//to avoid even palindrome..
break;

}
if(flag==strlen(a)/2)
cout <<" is palindrome";
else
cout <<"not";
getch();

}

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