Answer / ravinder singh rawat

#include<conio.h>
#include<stdio.h>
void main()
{ char *a,*count,s[11];
int i ;
printf("\n:enter string for Palindrome test\t");
scanf("%s",&s);
i= strlen(s);
a=(char *)malloc(i*sizeof(char));
a=&s[0];
count=&s[i-1];
while((*(a++)==*(count--)) && i>=1)
{ i--; }
if(i==0) { printf("\n%s is a palin",s);}
else { printf("\n%s is not palin",s);}
getch();
}

Answer / rajni

write a program for array to pointer and pointer of an
array?

Answer / vikas

thank you
i needed this
do u hv any more questions-answer on pointer

Answer / pradeep raj

int main()
{
char a[20],*p,*q;//p=>front pointer q=>back pointer
int flag=0;
cin >>a;
q=&a[0];
while(*q!='\0')
q++;
q--; // to the last character before null

for(p=&a[0];p!=q ;p++,q--)
{

if(*p==*q)
flag++;
if((q-p)==1)//to avoid even palindrome..
break;

}
if(flag==strlen(a)/2)
cout <<" is palindrome";
else
cout <<"not";
getch();

}

Answer / priyanka

#include<stdio.h>
#include<conio.h>
int stpal(char str[50]);
void main()
{
char str[50];
int pal;
clrscr();
printf(“nnt ENTER A STRING…: “);
gets(str);
pal = stpal(str);
if(pal)
printf(“nt THE ENTERED STRING IS A PALINDROME”);
else
printf(“nt THE ENTERED STRING IS NOT A PALINDROME”);
getch();
}
int stpal(char str[50])
{
int i = 0, len = 0, pal = 1;
while(str[len]!=’&#8242;)
len++;
len–;
for(i=0; i<len/2; i++)
{
if(str[i] == str[len-i])
pal = 1;
else
{
pal = 0;
break;
}
}
return pal;
}

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