Interested to Buy Any Domain ? << Click Here >> for more details...
If we have 15000kw connected load in a factory than how much
power demand sanction should be taken from electricity board.
Pls provide complete calculation.
- 3 Answers
- 8017 Views
- I also Faced
- E-Mail Answers
Answer Posted / rakesh maharjan
Remember the formula
KW=1.732 x V xI x PF
or
KW= KVA x PF, where PF = 0.8
connected load KW= Full load kw x 80%
Here in your case, connected load KW= 15000kw
so full load KW= 15000/80%=18750 KW
KVA= KW/.8
KVA=18750/.8=23437 KVA, this is the demand sanction.
I am junior Engineer.
Please verify by senior designer also.
| Is This Answer Correct ? | 5 Yes | 3 No |
Post New Answer View All Answers
What are the advantages & disadvantages of a group electrive drive?
what is efficient motors and how it is different from normal induction motors
What type of wiring series or parallel is used for conventional and addressable type FAS & why?
What cmos is and its benefits?
sir, i'm preparing for hpcl exam officer trainee pls tell me how the exam ques paper pls pls
What is star-delta transformer?
Can anybody inform me about the pattern of ECIL GET( Graduate Engineers Trainee) interview for Electrical students? Will there be HR round as well? I thought of preparing for 2 to 3 subjects thoroughly. Will it be sufficient? Please share your thoughts.
What is dc current source?
what kelvin's law ?
in india per day how much power is generated including all power station
i am completed my degree(B.E EEE) 2014 anychance to get electrical licence plz help me
Why do we mostly prefer to generate and distribute electricity in 3 phase and not in 4 phase or 5 phase?
what types of cable used in underground coal mining?
Explain using drawings what is reverse PID action w.r.t PID controllers.
what is the meaning of the symbol << >> put in transformer drawing
