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Answer Posted / mayur
Slip of belt
Belt drive is not a positive drive because of the insufficient friction between pulley and belt, the linear speed of rim of pulley and that of the belt on it are different. this difference is known as slip in the belt drive. Slip occurs due to motion of driver without carrying belt over it or motion of belt without taking follower with it.
Let S1 be the percentage slip between driver pulley and belt,
S2 be the percentage slip between belt and driven pulley and
v is the linear velocity of belt per minute.
v = π d1 N1 – π d1 N1 × S1 / 100
v = π d1N1 (1 – S1 / 100) …(1)
Similarly πd2N2 = v – v × S2 / 100 = v (1 – S2 / 100) …(2)
Putting value of v from eq. (1)
πd2N2 = πd1N1 (1 – S1 / 100) × (1 – S2 / 100)
N2 / N1 = d1 / d2 (1 – S1 / 100) × (1 – S2 / 100)
= d1 / d2 [1 – (S1 + S2 / 100)]
Let S = S1 + S2 be the total percentage of slip
N2 / N1 = d1 / d2 [(1 – S/100)]
If thickness of the belt (t) is considered then,
N2 / N1 = d1 + t / d2 + t (1 – S / 100)
If a number of pulleys are used to transmit power then
Nlast follower / Nfirst driver = d1.d3.d5… / d2.d4.d6… [1 – S/100]
where d1.d3.d5… are diameters of the drivers and d2.d4.d6 are diameters for the followers. S is total percentage of slip in all stages.
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