class base
{
public:
int fun(int)
{}
};
class base2
{
public:
int fun(float)
{
}
};
so here qustion is both function either function
overloading or over riding;
- 4 Answers
- 5841 Views
- Manhattan, I also Faced
- E-Mail Answers
Answer Posted / utpal kashyap
Overloading...
Because Function overloading depends upon type of parameters/number of parameters (NOT type of function) passed in function, So this is the example of function overloading.
| Is This Answer Correct ? | 11 Yes | 3 No |
Post New Answer View All Answers
Can I have a reference as a data member of a class? If yes, then how do I initialise it?
Write a program to add three numbers in C++ utilizing classes.
What is the use of volatile variable?
What are the new features that iso/ansi c++ has added to original c++ specifications?
What are arrays c++?
To what does “event-driven” refer?
Define namespace in c++?
What is low level language in simple words?
Is python written in c or c++?
Is c++ a pure oop language?
What are the main features of c++?
How many static variables are created if you put one static member into a template class definition?
When can I use a forward declaration?
Write about the scope resolution operator?
What it is and how it might be called (2 methods).
