class base { public: int fun(int) {} }; class base2 { public: int fun(f

class base
{
public:
int fun(int)
{}
};
class base2
{
public:
int fun(float)
{
}
};
so here qustion is both function either function
overloading or over riding;

Question Posted / chandrashekharswain

4 Answers
5838 Views
Manhattan, I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

class base { public: int fun(int) {} }; class base2 { public: int fun(float) { } }; so ..

Answer / utpal kashyap

Overloading...
Because Function overloading depends upon type of parameters/number of parameters (NOT type of function) passed in function, So this is the example of function overloading.

Is This Answer Correct ?

11 Yes

3 No

class base { public: int fun(int) {} }; class base2 { public: int fun(float) { } }; so ..

Answer / adarsh gumashta

Overloading would be possible if class 2 extended class1
but in the case its not there . so neither overloading nor overriding .

http://stackoverflow.com/a/14181786

Is This Answer Correct ?

3 Yes

0 No

class base { public: int fun(int) {} }; class base2 { public: int fun(float) { } }; so ..

Answer / sandeep mannarakkal

Over loading and overriding , both are performing in the same scope, here both functions have different scope.
So it is NOT overloading ,
NOT over riding.

Is This Answer Correct ?

0 Yes

0 No

class base { public: int fun(int) {} }; class base2 { public: int fun(float) { } }; so ..

Answer / keerthi

overriding

Is This Answer Correct ?

0 Yes

8 No

Post New Answer

More C++ General Interview Questions

Which operations are permitted on pointers?