Answer Posted / binoy

C++ program to print a diamond inside a box using asterisks.


#include<iostream.h>
#include<conio.h>
#include<math.h>
void main()
{
int i=0,j=0,num;
clrscr();
cout<<"Enter limit\n";
cin>>num;
cout<<endl;
for(i=-(num+2);i<=num+2;i++)
{
for(j=-(num+2);j<=num+2;j++)
{
if(abs(i)+abs(j)<=num||j==-(num+2)
||j==(num+2)||i==-(num+2)||i==(num+2))
{
cout<<"*";
}
else
{
cout<<" ";
}
}
cout<<endl;
}
getch();
}


Another solution for the same question :

http://programscpp.blogspot.in/2012/08/program-to-print-diamond-in-box-2.html

Assume an array of structure is in order by studentID field of the record, where student IDs go from 101 to 500. Write the most efficient pseudocode algorithm you can to find the record with a specific studentID if every single student ID from 101 to 500 is used and the array has 400 elements. Write the most efficient pseudocode algorithm you can to find a record with a studentID near the end of the IDs, say in the range from 450 to 500, if not every single student ID in the range of 101 to 500 is used and the array size is only 300

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