write a programming using for loop in c++ to generate diamond
trangel?
C++ program to print a diamond inside a box using asterisks.
#include<iostream.h>
#include<conio.h>
#include<math.h>
void main()
{
int i=0,j=0,num;
clrscr();
cout<<"Enter limit\n";
cin>>num;
cout<<endl;
for(i=-(num+2);i<=num+2;i++)
{
for(j=-(num+2);j<=num+2;j++)
{
if(abs(i)+abs(j)<=num||j==-(num+2)
||j==(num+2)||i==-(num+2)||i==(num+2))
{
cout<<"*";
}
else
{
cout<<" ";
}
}
cout<<endl;
}
getch();
}
Another solution for the same question :
http://programscpp.blogspot.in/2012/08/program-to-print-diamond-in-box-2.html
Is This Answer Correct ? | 6 Yes | 2 No |
how can i access a direct (absolute, not the offset) memory address? here is what i tried: wrote a program that ask's for an address from the user, creates a FAR pointer to that adress and shows it. then the user can increment/decrement the value in that address by pressing p(inc+) and m(dec-). NOW, i compiled that program and opened it twice (in 2 different windows) and gave twice the same address to it. now look what happen - if i change the value in one "window" of the program, it DOES NOT change in the other! even if they point to the same address in the memory! here is the code snippet: //------------------------------------------------------ #include <stdio.h> //INCLUDE EVERY KNOWN HEADER FILE #include <conio.h> //FOR ANY CASE... #include <iostream.h> #include <dos.h> #include <process.h> main() { int far *ptr; //FAR POINTER!!! long address; char key=0; //A KEY FROM THE KEYBOARD int temp=0; clrscr(); cout<<"Enter Address:"; cin>>hex>>address; //GETS THE ADDRESS clrscr(); (long)ptr=address; temp=*ptr; //PUTS THE ADDRESS IN THE PTR cout<<"["<<hex<<(unsigned long)ptr<<"]="<<*ptr<<" = "<< (char)(*ptr); //SHOWS: [address]=value=ASCII symbol. while (key!=27) //WHILE YOU DONT PRESS ESC. { while(!kbhit()) //WHILE KEY IS NOT PRESSED { if (temp!=*ptr) { temp=*ptr; clrscr(); cout<<"["<<hex<< (unsigned long)ptr<<"]="<<*ptr<<" = "<<(char)(*ptr); }; //IF THE VALUE HAS CHANGED, CLEAR THE SCREEN AND SHOW //AGAIN if (key=='p') {key=0; (*ptr)++; } //INCREMENT VALUE if (key=='m') {key=0; (*ptr)--; } //DEC. VALUE }; key=getch(); //IF A KEY IS PRESSED, READ IT FROM THE //KEYBOARD }; return 0; //IF ESC WAS THE KEY, EXIT THE PROGRAM } //---------------------------------------------------------
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Badboy is defined who has ALL the following properties: 1. Does not have a girlfriend and is not married. 2. He is not more than 23 years old. 3. The middle name should be "Singh" 4. The last name should have more than 4 characters. 5. The character 'a' should appear in the last name at least two times. 6. The name of one of his brothers should be "Ram" Write a method: boolean isBadBoy(boolean hasGirlFriend , boolean isMarried, int age , String middleName , String lastName , String[] brotherName); isHaveGirlFriend is true if the person has a girlfriend isMarried is true if the person is married age is the age of the person middleName is the middle name of the person lastName is the last name of the person brotherName is the array of the names of his brothers