i have a file which contains records like
10,30,90,50,20,40,80,60,70
i want to display these records in reverse order like
70,60,80,40,20,50,90,30,10
please give me the cobol code (do not sort the records)
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Answer Posted / ch.ranveer singh gurjar
ou can try this i will give 100% exact output...by
CH. RANVEER SINGH GURJAR
IDENTIFICATION DIVISION.
PROGRAM-ID. 'OCCURS'.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT INFILE ASSIGN TO DD1.
SELECT OUTFILE ASSIGN TO DD2.
DATA DIVISION.
FILE SECTION.
FD INFILE.
01 INREC.
05 IN-EMP-ID PIC X(5).
05 IN-EMP-NAME PIC X(10).
05 FILLER PIC X(65).
FD OUTFILE.
01
OUTREC.
05 OUT-EMP-ID PIC X(5).
05 OUT-EMP-NAME PIC X(10).
05 FILLER PIC X(65).
WORKING-STORAGE
SECTION.
01 WS-COUNT PIC 9(4) VALUE ZEROS.
01 EOF PIC X(1) VALUE 'N'.
01ARRAY1.
05 ARREC OCCURS 1 TO 50 TIMES DEPENDING ON WS-COUNT.
10 AR-EMP-ID PIC X(5).
10 AR-EMP-NAME PIC X(10).
PROCEDURE
DIVISION.
OPEN INPUT
INFILE.
OPEN OUTPUT
OUTFILE.
PERFORM MOVE-RECORD UNTIL EOF = 'Y'.
PERFORM PARA1 UNTIL WS-COUNT = ZEROS
CLOSE
INFILE.
CLOSE OUTFILE.
STOP RUN.
MOVE-RECORD.
READ INFILE AT END MOVE 'Y' TO EOF
NOT AT END
MOVE INREC TO ARREC(WS-COUNT)
ADD 1 TO WS-COUNT.
PARA1.
MOVE ARREC(WS-COUNT) TO OUTREC
WRITE OUTREC
SUBTRACT 1 FROM WS-COUNT.
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