i have a file which contains records like
10,30,90,50,20,40,80,60,70
i want to display these records in reverse order like
70,60,80,40,20,50,90,30,10
please give me the cobol code (do not sort the records)
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Answer Posted / preethi
Declare table , and a index variable in the working storage section.
Procedure Division.
Open file1.
perform para1 thru para1-exit until end-of-file.
perform display-para thru display-para-exit.
close file1.
go back.
Para1.
read file1 into ws-file1
at end
end-of-file
set index-diff to index
not at end
move ws-file1-num to table-num(index)
set index up by 1
end-read.
para1-exit.
exit.
Display-para.
subtract 1 from index-diff.
perform until index-diff = 0
display table-num(index-diff)
set index-diff down by 1
end-perform.
display-para-exit.
exit.
| Is This Answer Correct ? | 5 Yes | 3 No |
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