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I am working on a 11KV system with fault current of 40KA
for 1 second. I have selected 2500MVA 11/0.433KV
transformer.
How can i find the impedance value for this transformer?
Please help me.
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Answer Posted / kaushik
i don't understand the purpose of giving 1 second ......
but what i think solution will be
s.c mva=1.732*v*i.
s.c mva=1.732*11000*40000.
s.c mva=762.08 mva.
per unit impedence of the transformer will be= (base
mva)/(s.c mva)
taking transformer 2500kva(i think it is wrong 2500mva)
we get
=(2.5/762)*100=0.328% of tranformer impedence
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