Answer Posted / manish deswal

let us conside current p.f = .8 & improved to .9,
Load = 65 hp =65 * 746 = 48.49 KW
KVA1 = 48.49/.8= 60.61

KVAR = Squareroot of [ square(60.61)-square(48.49)]=36.36
KVA2 = 48.49/.9= 53.88

KVAR = Squareroot of [ square(53.88)-square(48.49)]=23.49

Increased Capacitor bank capacity = 36.36-23.49 = 12.87 KVAR

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