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input may any number except 1,output will always 1..
conditions only one variable should be declare,don't use
operators,expressions,array,structure
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Answer Posted / dana
#include<stdio.h>
#include<conio.h>
main()
{
int x;
printf{"enter the num ",x);
scanf("%d",&x);
if(x!=1)
printf("1");
else
printf(" ");
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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