A number when divided by D leaves a remainder of 8 and when
divided by 3D leaves a remainder of 21 . What is the
remainder left, when twice the number is divided by 3D?
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Answer Posted / manish vazirani
(number-8)/D = any integer ---(1) (since the remainder will
be zero)
(number-21)/3D = any integer --(2) (since the remainder will
be zero)
Multiply and divide lhs of equation 1 with 3
3x (number-8)/3D = any integer
=> (3x number-24)/3D = any integer--(3)
Now, subtract equation (2) from equation (3),
((3x number-24)/3D) - ((number-21)/3D) = any integer value
=> (2x number - 3)/3D = any integer value
the above equation satisfies the condition given in the
equation. Hence the answer is 3.
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