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If a person walks at 4/5th of his usual spee he reaches
40min late. If he walks athis usual speed how much time does
he travels.
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Answer Posted / anuradha
in both cases person cover the same distance
hence
let t min time taken to cover the distance with actual speed x
hence
xt=4/5x(t+40)
=160 min
=2 hr and 40 min
| Is This Answer Correct ? | 13 Yes | 2 No |
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