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how much cement,sand,aggregate will use for 1 cum in ratio of
1:2:4.
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Answer Posted / a.mohammed yahya
For all Common Grade of Concrete Quantity 1Cum fill the
1.57Cum(for 20mm size Jally)
So For the Ratio = 1: 2: 4 (Total = 1+2+4=8)
( there for 1 - Cement,2- sand,3- 20mm Size Jelly)
Calculate for Cement = 1/8 = 0.125
= 0.125 x 1.57
= 0.196
For Common 1Cum Cement Quantity = 1440kg
there for = 1440 x 0.196
Required Cement = 282kg
Calculate for Sand = 2/8 = 0.25
= 0.25x 1.57=0.393Cum
= 0.393 x 35.32
Required Sand =14 Cft
Calculate For Jelly = 4/8 = 0.5
= 0.5 x 1.57
= 0.79Cum
Required Jally = 0.79 x 35.32 = 28 cft
| Is This Answer Correct ? | 24 Yes | 33 No |
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