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generate this output using for loop

Answer Posted / varsha shukla

#include<conio.h>
#include<stdio.h>
void main()
{
int i,j,k,l;
for(i=1;i<=4;i++)
{
for(k=i;k<=4;k++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf(" %d",j);
}
printf("\n");
}
for(i=3;i>0;i--)
{
for(l=i;l<=3;l++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf(" %d",j);
}
printf("\n");
}
getch();

Is This Answer Correct ?    4 Yes 1 No



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