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generate this output using for loop

Answers were Sorted based on User's Feedback



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Answer / varsha shukla

#include<conio.h>
#include<stdio.h>
void main()
{
int i,j,k,l;
for(i=1;i<=4;i++)
{
for(k=i;k<=4;k++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf(" %d",j);
}
printf("\n");
}
for(i=3;i>0;i--)
{
for(l=i;l<=3;l++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf(" %d",j);
}
printf("\n");
}
getch();

Is This Answer Correct ?    4 Yes 1 No

1 1 2 1 2 3 1 2 3 4 ..

Answer / narasimharao

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k,n;
printf("Enter n value:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(k=i;k<n;k++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("%d",j);
for(k=i;k<i+1;k++)
{
printf(" ");
}
}
printf("\n");
}
for(i=n-1;i>=1;i--)
{
for(k=i;k<n;k++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("%d",j);
for(k=i;k<i+1;k++)
{
printf(" ");
}
}
printf("\n");
}
getch();
}

Is This Answer Correct ?    1 Yes 2 No

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