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A number when divided by D leaves a remainder of 8 and when
divided by 3D leaves a remainder of 21 . What is the
remainder left, when twice the number is divided by 3D?
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Answer Posted / chanki choudhary
(number-8)/D = any integer value (coz remainder 0)
(number-21)/3D = any integer value (coz remainder 0)
multiply with 2
2x(number-21)/3D = 2 x any integer value = integer
(2x number -42)/3D = integer value
so we can say that if we divide (2xnumber) with D remainder
should be 42
Again look
multiply and divide lhs of equation 1 with 3
3x (number-8)/3D = any integer value
(3x number-24)/3D = integer
subtract equation 1 from this equation
((3x number -24)/3D)-((number-8)/D)= large integer- small
integer
(2x number -3)/3D = integer value
so remainder should be 3
now we found 2 answers
3 and 42
actually both are right
but 3 is appropriate answer
we can conclude that number D is 39
so we got answer 42
| Is This Answer Correct ? | 9 Yes | 5 No |
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