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OUT OF 111 MARBLES ONE IS NOT OF SAME WEIGHT. HOW TO FIND
AND GIVE THE MIN. NO OF STEPS
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Answer Posted / rajinikanth budigelli
stp1:- 111 devide into 3 groups.Grp A-55, Grp B-55.Grp
C-1(hold C in hand)
Case1:if weight[A]=weight[B] then ans is C.
IF NOT
Case2:then c*55= weight[A(55)] or weight[B(55)].
step2:take the group which is not equal to c*55.
Step3:repeat step1 and 2.like
Grp D[1],Grp E[27] Grp F[27].
step4:compare E[27] ,F[27].
CASE1:if E[27]=F]27] THEN ANS IS D[1].
IF NOT
CASE2:VERIFY D[1]*27 E[27] & F[27].AND PICKUP THE
GROUP WHICH IS NOT EQUAL.
STEP 5: DEVIDE THE GROUP IN TO 3 GROUPS.
G[1],H[13],I[13]RESPECTIVELY.
STEP6:REPEAT STEP(4).COMPARE H[13],I[13].
CASE1:IF H[13]=I[13].THEN ANSWER IS G[1].
ELSE
CASE2: VERIFY G[1]*13=H[13] OR G[1]*13=I[13].
PICKUP THE GROUP WHICH IS NOT EQUAL TO G[1]*13.
STEP7.AGAIN DEVIDE IT INTO 3GROUPS. J[1],K[6]L[6].
COMPARE K[6]&L[6].
CASE 1:IF K[6]=L[6] THEN ANS IS J[1].
ELSE
CASE2:PICK UP THE GROUP WHICH IS NOT EQUAL TO J[1]*6.
STEP8:HERE WE HAVE 6 MARBLES IN THE GROUP. THEN DEVIDE AGAIN
IN TO 3 GROUPS.M[2],N[2]0[2]. THEN COMPARE M,N,O.
STEP 9:HERE WE GET ONLY TWO GROPS WITH SAME WEIGHT.EXP.IF
M[2]=N[2]THEN THEY R NOT EQUAL TO O[2].
STEP 10: HERE WE GET A GROUP WITH 2 MARBLES.COMPARE O1,O2
WITH ANY OTHER REFERENCE MARBLE.HERE WE KNOW THAT O1 IS NOT
EQUAL TO O2. IF O1=REF MARBLE THEN ANS IS O2.OR IF O2=REF
MARBLE THEN ANS IS O1 MARBLE.
then hold 1 marble D[1] make 2-groups E[27],F[27] repeat
step 1,2 and 3.
step5:if E=F then ans is D. if E[27] not equal to E[27]
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