2^n+1=2^n+1^n (2^(n-2))^2+(1^(n-2))^2 [ like a^2 + b^2 ] (2^(n-2)+1)*(

java program that takes a 3 digit number n and finds out
whether
the number 2^n + 1 is prime, or if it is not prime find out
its
factors.

Question Posted / nithi

Answer Posted / nithi

2^n+1=2^n+1^n
(2^(n-2))^2+(1^(n-2))^2 [ like a^2 + b^2 ]
(2^(n-2)+1)*(2^(n-2)-1)) [ like (a+b) (a-b) ]

So factors is 2^(n-2)+1),2^(n-2)-1)

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