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java program that takes a 3 digit number n and finds out
whether
the number 2^n + 1 is prime, or if it is not prime find out
its
factors.
- 7 Answers
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Answer / siva prasad
hi,
if n is 3 digit no.Then 2^n+1 is not a prime no.The no.of
factors r coming.
Ex: n=100 then 2^100=1.2676506002282294E30 .
| Is This Answer Correct ? | 4 Yes | 3 No |
Answer / ramu
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| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / vipul
public List checkPrime(int N) {
boolean isPrime = true;
List<Integer> list = new ArrayList<Integer>();
int p = 7;
for (int i = 2; i < p; i++) {
if (p % i == 0) {
isPrime = false;
list.add(i);
} else
isPrime = true;
}
if (isPrime) {
list.add(p);
}
return list;
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / nithi
2^n+1=2^n+1^n
(2^(n-2))^2+(1^(n-2))^2 [ like a^2 + b^2 ]
(2^(n-2)+1)*(2^(n-2)-1)) [ like (a+b) (a-b) ]
So factors is 2^(n-2)+1),2^(n-2)-1)
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / prabhu
Mr Nithi U'r Wrong If it is 2^n-1 than U'r correct
Because a^2 - b^2 = (a+b)*(a-b)
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / karuna
Mr Nithi U'r Wrong If it is 2^n-1
Then
2^n-1=2^n-1^n
(2^(n/2))^2-(1^(n/2))^2 [ like a^2 - b^2 ]
(2^(n/2)+1)*(2^(n/2)-1)) [ like (a+b) (a-b) ]
So factors is 2^(n/2)+1),2^(n/2)-1)
This also n is even and expect 2 .
2^n - 1 is not a prime.
n is odd and include 2 then
2^n - 1 is prime.
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / sibiraj
if n=3,then it is not prime .the no. of factors are 3.
(2^3+1 = 9.9 is not prime. 9 has the factors 1,3,9.)
| Is This Answer Correct ? | 1 Yes | 4 No |
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