Clearly Define Active,Reactive,Apparant power.Which
applications used which power above metioned power?
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Answer Posted / jayesh pillai
square of kva= square of kw + square of kvar
here, a power system possess apparent power i.e. kva
it is divided into two components i.e kw active power and
kvar reactive power
kw = kva*(cos phi) and kvar = kva (sin phi)
here actual power i.e. responsible as a loss component and
thus losses occurs in line due to active power
reactive power does not does any useful work but it is
responsible for building up magnetic field in motors or any
inductive equipments
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