How to calculate the no of bags required for 12mm thick 1:6
plastering?
Answer Posted / dinesh
Cement= 1 Sand = 6, assume W/C=0.4
Water = 0.4*1= 0.4
Total = 1+6+0.4=7.4
Wt per m3 of CM = 2400 kg
for 10 m2 = 1.2 cum CM reqd.
Cement required for 1 m3 = 2400/7.4 = 324.3 kg = 6.48 bags
so for 10m2 area of 12mm thick plaster = 1.2*6.48 = 7.78
Bags required.
| Is This Answer Correct ? | 13 Yes | 27 No |
Post New Answer View All Answers
What is the usage of zoom command?
How much quantity of cement,sand,stone used to build 1 cum of cc road??
If 40 backlogs are cleared m finally with 65 percent marks . Am I eligible to get visa to US
how can can column be corrected when the design is not safe ? is the increasing the clearcover a solution?
what is the formula for Mass of cement grout (Dg)=???
What is proportion of PCC Grade G?
What is difference between code and standard and specification?
what is called the inverd level of mabhole chamber?
What is the Maximum %age of Steel in columns and beams ?
Doul Bar reinforcement and details of drawing.
What is the release of lien?
how many running meters in one kilogram of 4mm pvc coated chainlink fencing
What are the different theories of failure under static load?
What is binding spacing of the rebars at lapping zones.
what is the metal ratio in granular subbase coarse for one cum ? And please explain the morth table ...what is the difference between grading 1 , 2, 3 what it means..plz explain