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What is the output of the program given below
#include<stdio.h>
main()
{
char i=0;
for(;i>=0;i++) ;
printf("%d\n",i);
}
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Answer Posted / ananth
The loop never gets terminated as it runs infinite. So the
printf statement will not trigger & no o/p is produced.
| Is This Answer Correct ? | 11 Yes | 19 No |
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