Write a query to find the name of employees those who have
joined on Monday.(based on column hire_date)

Answer Posted / sankarapandian

select *,upper(datename(dw,gedate())) as dayofweek from
employee where upper(Convert(varchar(15),datename dw,gedate
())))='MONDAY'

Is This Answer Correct ?    1 Yes 4 No



Post New Answer       View All Answers


Please Help Members By Posting Answers For Below Questions

Does truncate remove indexes?

721


What is an implicit commit?

762


What is pl sql collection?

694


How do I run pl sql in sql developer?

858


What are the two different parts of the pl/sql packages?

790






How do you update a sql procedure?

766


What is pivot table in sql?

736


Can cursors be part of a trigger body?

1350


What is primary key secondary key alternate key candidate key?

762


Table1: Col1 col2 1 2 10 3 4 89 5 6 Table:2 Col1 col2 3 2 9 5 4 7 6 87 With the help of table1 and table2 write a query to simulate the fallowing results. Output1: Col1 col2 1 2 2 3 3 4 4 5 5 6 Output2: Col1 col2 2 3 10 4 5 89 6 7 1.Write query for single row to multiple row using sql statements. Eg:a,b,c,d,e,f Change to A B C D E F 2. Write query for multiple row to single row using sql statements. Eg2 A B C D E F Change to Eg:a,b,c,d,e,f Table1: Col1 col2 8 5 2 9 4 2 5 1.Write a query to select all the rows from a table1,if the value of A is null then corresponding B’s value should be printed in A’s value.if the value of A is null in that table then corresponding B’s value should be printed as 30. 2. write a query to find the sum of A and B .display the max among both. 3.write a query to find total number of rows from table 1. Note: if any column value is null in a row then that row should be considered as 2 rows. 4.write a query to display all the records of table1 except A containg 2 as well B containg 5. 5.rewrite the fallowing without using join and group by. Select b.title,max(bc.returneddate –bc.checkoutdate)” mostdaysout” From bookshelf_checkout bc, Book shelf B Where bc.title(+)=b.title Group by b.title. 6.rewrite fallowing query Select id_category from category_master X where exists (select 1 from sub_category Y where X.id_category=Y.id_category) Customer: Name phone1 phone2 phone3 bitwise A 23456 67890 12345 --- B 67459 89760 37689 --- Don’t_call Col1 67890 37689 1.q) update the customer table of bitwise with 1 or 0. Exists in don’t_call table menas show -1 Other wise -0. Output. Name bitwise A 010 B 010

2220


How to run sql statements with oracle sql developer?

791


How to run sql*plus commands in sql developer?

801


How do I partition in sql?

704


Can a foreign key be a duplicate?

681


Is join and inner join the same?

724