Answer Posted / suresh

let the total volume of the concrete is = a
and let the given mix proportion is 1:1.5:3
then the quantity of the
cement required = a*(1.52/(1+1.5+3))m^3 = x m^3
we know that one cubic metre = 1450kg = 29 bags
1 cubic metre = 29 bags
x cubic metre = ?
=(x * 29)/1 bags

now, fine agg = 1.5*x
coarse agg = 3*x

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