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The matrix of a (7,9)was given.The address of the first byte
of a (1,1)matrix=1258.It takes 4 bytes to store the
number,then calculate the address of the last byte of a
(5,8) matrix??
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Answer Posted / snehal
(1,1)=1258
after tat for 1 it contain 8
for 2=9
for 3=9
for 4=9
for 5=8
total=43
43*4=172
n 1258+172=1430
| Is This Answer Correct ? | 8 Yes | 3 No |
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