Answer Posted / gurunadharaov

by the formula p=v*i*cos@
assume the load as 5kw and operating at 230v and also
assume the load as inductive (so the power factor is 0.5
pf lag)


now by formula
5000=230*i*0.5
i=50A
NOW CABLE SIZE MUST BE > LOAD
SO CABLE SIZE IZ 65SQMM(ITZ DSSEPEND ON AL/CU CABLE)

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