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Given an array of size N in which every number is between 1
and N, determine if there are any duplicates in it. You are
allowed to destroy the array if you like.
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Answer Posted / murugesh
If there are no duplicates, Sum of numbers should be equal
to (N(N+1))/2.
Otherwise, duplicate is present.
No duplicate:
------------
Say N = 5
{1,2,3,4,5}
5(6)/2 = 15
1+2+3+4+5 = 15
Therefore no duplicate.
Duplicate:
---------
{1,2,3,4,1}
Sum = 11
which is not equal to 15 (N(N+1)/2)
Therefore duplicate present.
| Is This Answer Correct ? | 1 Yes | 15 No |
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