Answer Posted / murugesh

If there are no duplicates, Sum of numbers should be equal
to (N(N+1))/2.

Otherwise, duplicate is present.

No duplicate:
------------

Say N = 5

{1,2,3,4,5}

5(6)/2 = 15

1+2+3+4+5 = 15

Therefore no duplicate.

Duplicate:
---------

{1,2,3,4,1}

Sum = 11

which is not equal to 15 (N(N+1)/2)

Therefore duplicate present.

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