void main() { int n; char *s[4]={"even","od

How to find the given no is odd or even without checking of
any condition and loops. (Hint: Using array)

Question Posted / ligory antony

Answer Posted / ligory antony

void main()
{
int n;
char *s[4]={"even","odd"};
printf("Enter the no.:");
scanf("%d",&n);
n=n%2;
printf("th no. is %s",s[n]);
getch();
}

Is This Answer Correct ?

6 Yes

4 No

Please Help Members By Posting Answers For Below Questions

What is a pointer and how it is initialized?

1109

What is the advantage of a random access file?

1150

Why is void main used?

1048

Why #include is used in c language?

1013

What is the basic structure of c?

1033

What are dangling pointers in c?

1153

What is the difference between malloc() and calloc() function in c language?

1044

How many levels of pointers can you have?

1148

What are the types of data types and explain?

1049

What are the modifiers available in c programming language?

1186

What does nil mean in c?

1200

What is array of pointers to string?

1019

what is uses of .net

1697

Explain what does the function toupper() do?

1023

Which one to choose from 'initialization lists' or 'assignment', for the use in the constructor?

1047