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How to find the given no is odd or even without checking of
any condition and loops. (Hint: Using array)
- 4 Answers
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Answer / amala v
import java.io.*;
public class even {
public static void main(String arg[])throws
IOException
{
String a[]={"even","odd"};
BufferedReader br=new BufferedReader(new
InputStreamReader(System.in));
int n;
System.out.println("Enter no to find");
n=Integer.parseInt(br.readLine());
n=n%2;
System.out.println("given no is "+a[n]);
}
}
| Is This Answer Correct ? | 12 Yes | 3 No |
Answer / vaishu
void main()
{
int n;
char s[]={"even","odd"};
printf("Enter the no.:");
scanf("%d",&n);
n=n%2;
printf("th no. is %s",s[n]);
getch();
}
| Is This Answer Correct ? | 12 Yes | 7 No |
Answer / ligory antony
void main()
{
int n;
char *s[4]={"even","odd"};
printf("Enter the no.:");
scanf("%d",&n);
n=n%2;
printf("th no. is %s",s[n]);
getch();
}
| Is This Answer Correct ? | 6 Yes | 4 No |
Answer / anandi
void main()
{
int n;
char s[20][20]={"even","odd"};
printf("Enter the no.:");
scanf("%d",&n);
n=n%2;
printf("th no. is %s",s[n]);
getch();
}
| Is This Answer Correct ? | 3 Yes | 3 No |
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