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How to find the given no is odd or even without checking of
any condition and loops. (Hint: Using array)

Answers were Sorted based on User's Feedback



How to find the given no is odd or even without checking of any condition and loops. (Hint: Using ..

Answer / amala v

import java.io.*;
public class even {
public static void main(String arg[])throws
IOException
{
String a[]={"even","odd"};
BufferedReader br=new BufferedReader(new
InputStreamReader(System.in));
int n;
System.out.println("Enter no to find");
n=Integer.parseInt(br.readLine());
n=n%2;
System.out.println("given no is "+a[n]);

}

}

Is This Answer Correct ?    12 Yes 3 No

How to find the given no is odd or even without checking of any condition and loops. (Hint: Using ..

Answer / vaishu

void main()
{
int n;
char s[]={"even","odd"};
printf("Enter the no.:");
scanf("%d",&n);
n=n%2;
printf("th no. is %s",s[n]);
getch();
}

Is This Answer Correct ?    12 Yes 7 No

How to find the given no is odd or even without checking of any condition and loops. (Hint: Using ..

Answer / ligory antony

void main()
{
int n;
char *s[4]={"even","odd"};
printf("Enter the no.:");
scanf("%d",&n);
n=n%2;
printf("th no. is %s",s[n]);
getch();
}

Is This Answer Correct ?    6 Yes 4 No

How to find the given no is odd or even without checking of any condition and loops. (Hint: Using ..

Answer / anandi

void main()
{
int n;
char s[20][20]={"even","odd"};
printf("Enter the no.:");
scanf("%d",&n);
n=n%2;
printf("th no. is %s",s[n]);
getch();
}

Is This Answer Correct ?    3 Yes 3 No

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