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1)
int i=5;
j=i++ + i++ + i++;
printf("%d",j);This code gives the answer 15.But if we
replace the value of the j then anser is different?why?
2)int i=5;
printf("%d",i++ + i++ + i++);
this givs 18.
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Answer Posted / raghu
In the first case
initially j=15 is assigned that is (5+5+5).then i gets incremented thrice.if we try to print i then i will be
8 (5 is incremented thrice).
In the second case
as we know that printf gets evaluated 4m right to left
that is pf("%d", 5++ + 5++ +5++);
that means 4m right to left 7+6+5=18
firstly i's value is 5 then it gets incremented 6 then 7.
| Is This Answer Correct ? | 42 Yes | 14 No |
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