Answer Posted / siheng

the question was lifted from the SAT test prep source
the choices given were

A) x^2 + 1 = 0
B) x^2 - x - 2 = 0
C) x^2 - 10x - 5 = 0
D) 2x^2 - 2 = 0
E) x^2 - 2x - 3 = 0

the roots are 5, 1

but which of the following equations, a, b, c, d or e has a
root in common with x^2 - 6x + 5

the answer is D) 2x^2 -2 = 0

this is because when factored, the equation becomes

2(x^2 - 1) = 0

and the root of the equation therefore is

x^2 - 1 = 0
x^2 = 1
x = 1 ^1/2
x = 1 (since the square root of 1 is 1), which is common
with x^2 - 6x + 5

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