Answer Posted / thowsif_emerson_csm team

For 300 KVA the Full load Current=KVA*PF,
i.e 300x.8=240000 Watts.

we know in 3 Phase Circuits,

P=1.732x V x I x Pf,

I=P/1.732xV x Pf,

I=240000/1.732 X 440 X 0.8,

Full Load Current, I =240000/609=394 Amps,

The Load Current @ 40% is 394*.40=158 A(Total Load Current).

The Load Current @ 45% is 394*.45=177 A(Total Load Current).


So load current at 40% Load is 39*.40=15.6 A/Phase Amps.

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