Answer Posted / ashish

just add as many n(length of array) to an index as much it
has duplicates i.e. if array has size 7 and no. 5 is written
3 times then add 7 three times.so that after first loop
completion, you can just take division (a[5-1]/7 in this
case.so u got 3.)


//array is a[]
//len=length of array


for(i=0;i<len;i++)
{
b=a[i]%len;
a[b-1]=a[b-1]+7;
}
//printing output
for(i=0;i<len;i++)
{
cout<<i+1<<" occurs: "<<(a[i]/7)<<endl;
}

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