Answer Posted / jitendera kuaar sinha

hi arshad
here is expalnation
i have mistaly write next sunet id that is
192.168.10.0 192.168.10.63****( my mistake it start
from (192.168.10.64)
----------- ------------
----------- ------------
192.168.10.63 192.168.10.126

if this is your point of confusion then i ma soory i donot
know how i have writenn it.

now how to detrmine the exact block size and what will be
next sunet id(it also called n/w id)
then i am going to explain again
what was the given ip address
192.168.10.0/26
ok 2 bit of subnating i.e two bit is taken from host bit
i.e

128 64 32 16 8 4 2 1
1 1 0 0 0 0 0 0
tha is two bit is taken from host
now how many n/w will be made 2^2-2=2(acording to cosco
nither 4)
how many bit for host it is 6
numer of host / sunet=2^6-2=62
what is the mask of that given ip
255.255.255.192
what is the block size=256-192=64******************
block size consern with how many ip address should be
reside in the single n/w pool
that is therer is 64 ip address reside in the pool.now if
we started it with 0 than 64th ip address is end with 63
count 0 to 63 how many bit is it 64 if not then count again
(kidding)ok
so one pool is end with 63 then next pool with started at
what is it 64? yeas and go the 127 again 64 host
now any confusion?
the try to solve that question which i have provide and
there is another probem i am providing try to solve i am
90% sure you canot but try?


what is the n/w id and the brodcast id for the ip address
192.168.10.56/27

try it then i wiil send the tutreala about vlsm design in
claas c

scince first one is n/w id the last one is broadcast id
then vallid host ip address is 62(see the formula)

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