String reverse with time complexity of n/2 with out using
temporary variable.
Answer Posted / mm chen
#include <iostream>
#include <string>
using std::string;
using std::cout;
using std::endl;
using std::cin;
int main()
{
string s("abcdefghijklmnopqrstuvwxyz");
string::size_type s_size = s.size();
for (string::size_type x = 0; x != s_size; x++){
if ( (s_size -x -1) > x ){
s[x] ^= s[s_size - x -1];
s[s_size - x -1] ^= s[x];
s[x] ^= s[s_size - x -1];
}else{
break;
}
}
cout << s << endl;
}
Is This Answer Correct ? | 3 Yes | 0 No |
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