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A car travels a certain distance taking 7 hrs in forward
journey, during the return journey increased speed
12km/hr takes the times 5 hrs.What is the distance travelled
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10Kms
20Kms
30Kms
40Kms
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Answer Posted / priyanka saraf
s= d/7 forward (speed = dist/time)
s+12 = d/5 return journey
7s=d == 5s+60=d
==> 7s=5s+60
==> s = 30
==> d = 7*s
= 7*30
= 210
| Is This Answer Correct ? | 29 Yes | 8 No |
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