Answer Posted / alok sinha

Hello Boyz !!

Get excited to see this example thru

declare
--
varx1 number := 0;
varx2 number := 0;
varx3 number := 3;
--
begin
--
--
dbms_output.put_line('In: Varx #1 : initial value :: ' ||
varx1);
dbms_output.put_line('In: Varx #2 : initial value :: ' ||
varx2);
--
dbms_output.put_line('In: Varx #3 : Initial value :: ' ||
varx3);
dbms_output.put_line('

');
dbms_output.put_line('Hhhmmmnnn
Hhhmmmnnn Hhhmmmnnn ');
dbms_output.put_line('

');
--
--
varx3 := xx_func(varx3, varx1, varx2);
--
--
dbms_output.put_line('------------------------------------
--------------');
dbms_output.put_line('---------- Post Function -----------
------');
dbms_output.put_line('------------------------------------
--------------');
dbms_output.put_line('

');
dbms_output.put_line('------------------------------------
--------------');
dbms_output.put_line('Return Value :: Varx #3 :: returned
from function :: '|| varx3);
dbms_output.put_line('Out: Varx #1 : returned from
function :: '|| varx1);
dbms_output.put_line('Out: Varx #2 : returned from
function :: '|| varx2);
--
end;


create or replace function xx_func(north in number, east in
out number, west in out number ) return number is
south number;
begin
south := north + 4;
east := 4;
west := 5;
--
return south;
end xx_func;

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---

Table1: Col1 col2 1 2 10 3 4 89 5 6 Table:2 Col1 col2 3 2 9 5 4 7 6 87 With the help of table1 and table2 write a query to simulate the fallowing results. Output1: Col1 col2 1 2 2 3 3 4 4 5 5 6 Output2: Col1 col2 2 3 10 4 5 89 6 7 1.Write query for single row to multiple row using sql statements. Eg:a,b,c,d,e,f Change to A B C D E F 2. Write query for multiple row to single row using sql statements. Eg2 A B C D E F Change to Eg:a,b,c,d,e,f Table1: Col1 col2 8 5 2 9 4 2 5 1.Write a query to select all the rows from a table1,if the value of A is null then corresponding B’s value should be printed in A’s value.if the value of A is null in that table then corresponding B’s value should be printed as 30. 2. write a query to find the sum of A and B .display the max among both. 3.write a query to find total number of rows from table 1. Note: if any column value is null in a row then that row should be considered as 2 rows. 4.write a query to display all the records of table1 except A containg 2 as well B containg 5. 5.rewrite the fallowing without using join and group by. Select b.title,max(bc.returneddate –bc.checkoutdate)” mostdaysout” From bookshelf_checkout bc, Book shelf B Where bc.title(+)=b.title Group by b.title. 6.rewrite fallowing query Select id_category from category_master X where exists (select 1 from sub_category Y where X.id_category=Y.id_category) Customer: Name phone1 phone2 phone3 bitwise A 23456 67890 12345 --- B 67459 89760 37689 --- Don’t_call Col1 67890 37689 1.q) update the customer table of bitwise with 1 or 0. Exists in don’t_call table menas show -1 Other wise -0. Output. Name bitwise A 010 B 010

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