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write a program to sum of its digit with using control
structure or with out using loop. for ex: let the number is
25634 then answer will be=2+5+6+3+4=20
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Answer / alex r.
// without loop
// for digit in DEC
#include <stdio.h>
int sum(int digit)
{
if (digit%10 != digit)
return digit%10 + sum(digit/10);
return digit;
}
int main(void)
{
int digit = 25634;
printf("\nSum:%d", sum(digit));
return 0;
}
| Is This Answer Correct ? | 15 Yes | 7 No |
Answer / lalabs
// assume that num is non-negative.
int sum_digits_recursive ( int num )
{
if ( num == 0 ) return 0;
return (num % 10 + sum_digits_recursive ( num / 10 ));
}
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / rama krishna sidhartha
#include <stdio.h>
#include<conio.h>
void main()
{
int s=0,c,n;
clrscr();
printf("\n ENTER A VALUE : ");
scanf("%d",&n);
while(n>0)
{
c=n%10;
s=s+c;
n=n/10;
}
printf("\n THE SUM OF INDIVIDUAL DIGITS : %d",s);
getch();
}
| Is This Answer Correct ? | 10 Yes | 10 No |
Answer / thiruapthi rao
// mainlogic
while(number>0)
{
remainder=number%10;
sum=sum+remainder;
number=number/10;
}
/*
number=123
sum=1+2+3=6
*/
| Is This Answer Correct ? | 0 Yes | 1 No |
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