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A rich man died. In his will, he has divided his gold coins
among his 5 sons, 5 daughters and a manager.
According to his will: First give one coin to manager. 1/5th
of the remaining to the elder son. Now give one coin to the
manager and 1/5th of the remaining to second son and so
on..... After giving coins to 5th son, divided the remaining
coins among five daughters equally.
All should get full coins. Find the minimum number of coins
he has?
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Answer / guest
We tried to find out some simple mathematical method and
finally we wrote small C program to find out the answer. The
answer is 3121 coins.
Here is the breakup:
First son = 624 coins
Second son = 499 coins
Third son = 399 coins
Forth son = 319 coins
Fifth son = 255 coins
Daughters = 204 each
Manager = 5 coins
| Is This Answer Correct ? | 18 Yes | 6 No |
Answer / ranjith naidu
can explain that answer how u will get it
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / guest
Could you please explain how you got the answer 3121??
| Is This Answer Correct ? | 3 Yes | 4 No |
Answer / eveline
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| Is This Answer Correct ? | 0 Yes | 4 No |
Answer / hokuandphatty
Rich man has a minimum of 16,406 coins.
The breakdown is:
1st son = 3,281 coins
2nd son= 656 coins
3rd son = 131 coins
4th son = 26 coins
5th son = 5 coins
Each daughter = 4 coins
| Is This Answer Correct ? | 1 Yes | 10 No |
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