To find whether a number is even or odd without using any
conditional operator??
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Answer / kala
main()
{
int n;
printf("enter the number\n");
scanf("%d",&n);
if(n%2==0){
printf("number is even");}
else{
printf("number is odd");
}
}
or
if(n&1==0)
printf("even number");
else
printf(odd number");
| Is This Answer Correct ? | 31 Yes | 38 No |
Answer / sahithya
void main()
{
int n;
printf("enter n:");
scanf("%d",&n);
if(n%2==0)
printf( "even");
else
printf("odd");
}
| Is This Answer Correct ? | 15 Yes | 34 No |
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