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array contains zeros and ones as elements.we need to bring
zeros one side and one other side in single parse.
ex:a[]={0,0,1,0,1,1,0,0}
o/p={0,0,0,0,0,1,1,1}
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Answer / manoj
#include<stdio.h>
#include<conio.h>
void main()
{
int a[]={0,0,1,0,1,1,0,0};
int *arrayTemp = a;
int i, j_0 = 0, j_8 = 8;
for(int data = 0; *a != '\0'; *a++)
{
data = *a;
if(data == 1 )
{
a[j_0++] = data;
}
else
{
a[j_8--] = data;
} // if-else block
}//for loop
}//main function
for(i=0; i< 8; i ++)
{
printf("array value is %d", a[i]);
}
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / satinder singh
I Hope this will also work for this question.
I just took it for length of 8 but we can extend it to any
level.
void swap(int* p, int x, int y)
{
int tmp;
tmp = *(p+x);
*(p+x) = *(p+y);
*(p+y) = tmp;
}
int main()
{
int* ptr = (int*)malloc(sizeof(8));
int c, i, j;
for(c=0; c<8 ; c++) scanf("%d", ptr+c);
for(i=0; i<8; i++)
{
for(j=0; j<8; j++)
{
if( *(ptr+j) > *(ptr+j+1) ) swap(ptr, j, j+1);
}
}
for(c=0;c<8;c++) printf("%d", *(ptr+c));
return 0;
}
| Is This Answer Correct ? | 2 Yes | 8 No |
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